{"id":756532,"date":"2021-06-23T20:39:43","date_gmt":"2021-06-24T03:39:43","guid":{"rendered":"https:\/\/www.microsoft.com\/en-us\/research\/?post_type=msr-research-item&p=756532"},"modified":"2021-06-25T11:32:51","modified_gmt":"2021-06-25T18:32:51","slug":"optimal-regret-algorithm-for-pseudo-1d-bandit-convex-optimization","status":"publish","type":"msr-research-item","link":"https:\/\/www.microsoft.com\/en-us\/research\/publication\/optimal-regret-algorithm-for-pseudo-1d-bandit-convex-optimization\/","title":{"rendered":"Adversarial Dueling Bandits"},"content":{"rendered":"

We introduce the problem of regret minimization in Adversarial Dueling Bandits. As in classic Dueling Bandits, the learner has to repeatedly choose a pair of items and observe only a relative binary `win-loss’ feedback for this pair, but here this feedback is generated from an arbitrary preference matrix, possibly chosen adversarially. Our main result is an algorithm whose $T$-round regret compared to the \\emph{Borda-winner} from a set of $K$ items is $\\tilde{O}(K^{1\/3}T^{2\/3})$, as well as a matching $\\OmesdfsdfK^{1\/3}T^{2\/3})$ lower bound. We also prove a similar high probability regret bound. We further consider a simpler \\emph{fixed-gap} adversarial setup, which bridges between two extreme preference feedback models for dueling bandits: stationary preferences and an arbitrary sequence of preferences. For the fixed-gap adversarial setup we give an $\\smash{ \\tilde{O}((K\/\\Delta^2)\\log{T}) }$ regret algorithm, where $\\Delta$ is the gap in Borda scores between the best item and all other items, and show a lower bound of $\\OmesdfsdfK\/\\Delta^2)$ indicating that our dependence on the main problem parameters $K$ and $\\Delta$ is tight (up to logarithmic factors).<\/p>\n","protected":false},"excerpt":{"rendered":"

We introduce the problem of regret minimization in Adversarial Dueling Bandits. As in classic Dueling Bandits, the learner has to repeatedly choose a pair of items and observe only a relative binary `win-loss’ feedback for this pair, but here this feedback is generated from an arbitrary preference matrix, possibly chosen adversarially. Our main result is 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Saha","user_id":39835,"rest_url":"https:\/\/www.microsoft.com\/en-us\/research\/wp-json\/microsoft-research\/v1\/researchers?person=Aadirupa Saha"},{"type":"text","value":"Tomer Koren","user_id":0,"rest_url":false},{"type":"user_nicename","value":"Yishay Mansour","user_id":32793,"rest_url":"https:\/\/www.microsoft.com\/en-us\/research\/wp-json\/microsoft-research\/v1\/researchers?person=Yishay 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